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5
Figure 10. Rectification Waveform Efficiency
f, FREQUENCY (kHz)
2.0
1.0
60
20
10
6.0
3.0 5.0 1007.0 10 20 30 50
70
8.0

, EFFICIENCY FACTOR
40
TJ
= 25
°C
CURRENT INPUT WAVEFORM
Figure 11. Single±Phase Half±Wave Rectifier Circuit
RECTIFICATION EFFICIENCY NOTE
RS
RL
VO
The rectification efficiency factor σ
shown in Figure 10
was calculated using the formula:
σ

P(dc)
P

(rms)
V2o(rms).100%

R
V2o(ac)

V2o(dc)
.100%
L
V2o(dc)
RL
V2o(dc)
(1)
For a sine wave input Vm
sin (
ωt) to the diode, assume
lossless, the maximum theoretical efficiency factor
becomes:
σ(sine)

V2m
.100%

4
π2
.100%

40.6% (2)
V2m
2RL
4RL
For a square wave input of amplitude Vm, the efficiency
factor becomes:
R
σ(square)

L
V2m.100%

50% (3)
V2m
2
RL
(A full wave circuit has twice these efficiencies)
As the frequency of the input signal is increased, the
reverse recovery time of the diode (Figure 9) becomes
significant, resulting in an increasing ac voltage component
across RL
which is opposite in polarity to the forward
current, thereby reducing the value of the efficiency factor
σ, as shown on Figure 10.
It should be emphasized that Figure 10 shows waveform
efficiency only; it does not provide a measure of diode
losses. Data was obtained by measuring the ac component of
VO
with a true rms ac voltmeter and the dc component with
a dc voltmeter. The data was used in Equation 1 to obtain
points for Figure 10.
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